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73. An elevator has a mass of 4500kg and can carry a maximum load of 1800kg. If the cab is moving upward at full load at 3.8m/s, what power is required of the force moving the cab to maintain that speed? mg F a F mg kg m s kN F mg F F F m kg kg kg a a net a g total (6300 )(9.8 / ) 61.74 0 0 4500 1800 6300 2 An elevator, as illustrated, is being lifted up an elevator shaft by a steel cable. When the elevator is moving up the shaft at a constant velocity; (A) the upward force on the elevator by the cable is greater than the downward force of gravity.
Since the elevator is moving downwards and slowing down, there must be more upwards force The applied force is upwards and rightwards. Its upward component contributes to the upwards Fnorm The object is moving in a circle at constant speed. All the forces acting upon the object are equal.
moving in a circle at constant speed. Which statement best explains why the speed of the. satellite does not change although there is a net force Questions 49 through 52 pertain to the situation described below: A 1500-kg car travels at a constant speed of 22 m/s around a circular track that...
Note that constant velocity means constant speed plus constant direction that means along a straight line. Solution: The force of the elevator onto the person is nothing but the normal reaction, N, of the elevator floor onto his feet. For each case, a force diagram must be drawn.
A 1500-kg car traveling at 12.0 m/s is rammed from behind by a 2200 kg truck traveling in the same direction. No brakes are ever applied, and the two vehicles lock together upon collision and move together at 19.0 m/s. Calculate the initial speed of the truck. (Answer: 24.0 m/s)
An elevator, as illustrated, is being lifted up an elevator shaft by a steel cable. When the elevator is moving up the shaft at a constant velocity; (A) the upward force on the elevator by the cable is greater than the downward force of gravity.
*8 (p.174 Ex.57) An elevator cable breaks when a 755-kg elevator is 22.5m above the top of a huge spring (k = 8.00 x 10 4 N/m) at the bottom of the shaft. Calculate ( a ) the work done by gravity on the elevator before it hits the spring; ( b ) the speed of the elevator just before striking the spring; ( c ) the amount the spring compresses ...
A 5.0-kg mass is suspended by a string from the ceiling of an elevator that is moving upward with a speed which is decreasing at a constant rate of 2.0 m/s in each second. What is the tension in the string supporting the mass? a. 49 N . b. 39 N . c. 59 N . d. 10 N . e. 42 N . 19. A person weighing 0.70 kN rides in an elevator that has an upward ...
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An elevator, fully loaded with passengers, has a mass of 4000 kg. What power must be delivered by the motor (tension in the cable) so that the elevator moves up at constant speed of 2.0 m/s? A) 78.4 kW B) 18.4 kW C) 71.3 W D) 80.0 kW E) 98.2 kW Ans: Power 4000 9.8 2 78.4 kW u u Tv mgv Q10. A student lifted his bag to a height h. The work done ...
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would prefer to keep moving upward at a constant speed, so the elevator floor and scale effectively drop out a little bit from underneath the person as the elevator slows down. The person doesn't float upward, because again the elevator and the person move together, but the contact force between the person and the scale is reduced. 12. A toy train of m=0.60 kg moves at 20m/s along a straight track. It bumps into another train of M=1.5kg moving in the same direction. They stick together and continue on the track at a speed 12 m/s. What was the speed in m/s of the second train just before the collision? a. 12 b. 1.1 c. 8.8 d. 42 e. 9.2
The loaded cab of an elevator has a mass of 3.0 × 103 kg and moves 210m up the shaft in 23s at constant speed. At what average rate does the force from the cable do work on the cab? Solution: The elevator is moving at constant speed, so a = 0, so by N1L there is no net force on the cab. So the tension in the cable is T = mg = 3000 × 9.8 = 29 ...
A 2.0-kg block slides on a frictionless 25° inclined plane. A force of 4.6 N acting parallel to the incline and up the incline is applied to the block. What is the acceleration of the block? 1) 1.8 m/s2 up the incline 2) 2.3 m/s2 up the incline 3) 6.6 m/s2 down the incline 4) 1.8 m/s2 down the incline 5) 2.3 m/s2 down the incline Take my inertia to be 70 kg and treat my body like a particle (i.e. a mass that is concentrated at a single point). 2*. A motor must lift a 1000 kg elevator cab. The cab’s maximum occupant capacity is 400 kg, and its constant \cruising" speed is 21.5 m/s. The design criterion is that the cab must achieve this speed within 2.0 s at constant
12. A 1500-kg elevator moves upward with constant speed through a vertical distance of 25 m. How much work was done by the tension in the cable? A) 990 J B) 8100 J C) 140 000 J D) 370 000 J E) 430 000 J 13. A 12-kg crate is pushed up an incline from point A to point B as shown in the figure.
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=2.0 kg and . m. B =5.0 kg are on inclines and are connected together by a string as shown in Fig. 5–37. The coefficient of kinetic friction between each mass and its incline is m. k =0 30.. If . m. A. moves up, and . m. B. moves down, determine their acceleration. 29. (II) A child slides down a slide with a 34° incline, and at the bottom ...
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7. An elevator and its load have a combined mass of 1600 kg. Find the tension in the supporting cable when the elevator, originally moving downward at 12 m/s, is brought to rest with constant acceleration in a distance of 42 m. 8. A 60 kg woman stands in an elevator that is accelerating downward at 3.1 m/s2. Calculate the A) contin to move to the right with a constant speed. B) continu move to the right, with its speed decreasing with time. D) ontinuetð ovegto the right, with its speed increasing with time. up 10. A 65-kg ice skater pushes off his pa er and accelerates backwards at 1.3 m/s2. If the partner accelerates in the opposite direction at 2.0 m/s2, what ...
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A 1500 kg elevator moves upward with constant speed
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When the ship is moving full steam ahead at maximum speed (a constant speed), its acceleration is zero: 0 0. 13.28 A 3-kg block rests on top of a 2-kg block supported by but not attached to a spring of constant 40 N/m. The upper block is suddenly removed.The aircraft will continue to move and gain speed until thrust and drag are equal. In order to maintain a constant airspeed, thrust and drag must remain equal, just as lift and weight must be equal to maintain a constant altitude.
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...moves upward for 3.00 s with constant acceleration until it reaches its cruising speed, 1.75 m/s. (a) What is the average power of the elevator motor during a.) Firstly Power = Work/time Work = Force x Distance So we know acceleration is constant so we can use constant acceleration formulae. lets...
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C) a 490-kg elephant walking with a speed of 1.0 m/s D)a 1500-kg car at rest in a parking lot 39.Which object has the greatest inertia? A) downward at constant speed B) upward at constant speed C) downward at increasing speed D)upward at increasing speed 40.A person is standing on a bathroom scale in an elevator car.
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What is the speed of the bolt just as it hits the elevator floor (b) according to an observer in the elevator? (c) According to an observer standing on one of the floor This is part of a here. Okay, so we're gonna let why be the upward direction and why zero b the initial point of the floor of the elevator.When the ship is moving full steam ahead at maximum speed (a constant speed), its acceleration is zero: 0 0. 13.28 A 3-kg block rests on top of a 2-kg block supported by but not attached to a spring of constant 40 N/m. The upper block is suddenly removed.A constant frictional force of 4.0 X 10^3 retards the elevator's motion upward. What minimum power, in kilowatts, must the motor deliver to left the fully loaded elevator at a constant speed of 3.0 m/s? Here's what you know, m = 1000 + 800 = 1800 kg and v = 3.0 m/s and Fr = 4.0 X 10
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Sep 02, 2014 · Special Focus: Graphical Analysis 2000 Physics B, Question 1 A 0.50 kg cart moves on a straight horizontal track. The graph of velocity v versus time t for the cart is given below. a. Indicate every time t for which the cart is at rest. b. Indicate every time interval for which the speed (magnitude of velocity) of the cart is increasing. c.
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We find that each 90 min (2000 Mm) parcel of slow wind has near-constant speed yet exhibits repeatable, systematic charge state and composition variations that span the entire range of statistically determined slow solar wind values. The classic composition-velocity correlations do not hold on short, approximately hour long, time scales ... What is the scale reading if the elevator has an acceleration of (a) 1.8 m/s2 up? (b) 1.8 m/s2 down? (c) 9.8 m/s2 down? (828 N, 571 N, zero) 9) An elevator starts from rest with a constant upward acceleration. It moves 2.0 m in the first 0.60 s. A passenger in the elevator is holding a 3.0 kg package by a vertical string.
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Snapshot 1: the elevator accelerates upward; you feel heavier. Snapshot 2: the elevator is at rest; the scale shows your actual weight. Snapshot 3: the acceleration of the elevator is downward and equal to the acceleration due to gravity; you and the elevator can be considered to be in free fall, because the scale does not exert any force
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15. A 0.50-kg object moves in a horizontal circular track with a radius of 2.5m. An external force of 3.0N, always tangent to the track, causes the object to speed up as it goes around. The work done by the external force as the mass makes one revolution is: A. 24J B. 47J C. 59J D. 94J E. 120J ans: B 16. newtons, the elevator must be the surface ofthe Moon. The acceleration due to 1 accelerating upward gravity on the Moon is 2 accelerating downward (1) 0.0 m/s2 3 moving upward at constant speed 4 moving downward at constant speed A box decelerates as it moves to the right along a horizontal sur face, as shown in the diagram at the right. May 04, 2016 · A 1500 kg elevator moves up and down on a cable. Calculate the tension in the cable for the following cases: The elevator moves at constant speed upward The elevator moves at constant speed downward
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38. A 1500 kg elevator moves up and down on a cable. Calculate the tension in the cable for the following cases: a. The elevator moves at constant speed upward b. The elevator moves at constant speed downward c. The elevator accelerates upward at a constant rate of 1.2 m/s d. The elevator accelerates downward at a constant rate of 1.2 m/s 2 2 39. Initially, as the elevator accelerates upward, your weight reported by a scale will increase. While you're moving up or down at constant speed, the situation is exactly the same as standing on the ground. The scale reads your weight, and the springs are in the same condition as they are when the...
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